提交 53c1aa5f authored 作者: Thomas Mueller's avatar Thomas Mueller

Conditions of the form columnName IS NULL now use an index.

上级 c05cc247
......@@ -3025,8 +3025,8 @@ inner join test2 on test1.id=test2.id left
outer join test3 on test2.id=test3.id
where test3.id is null;
> PLAN
> -----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
> SELECT TEST1.ID, TEST2.ID, TEST3.ID FROM PUBLIC.TEST1 /* PUBLIC.TEST1.tableScan */ INNER JOIN PUBLIC.TEST2 /* PUBLIC.PRIMARY_KEY_4C: ID = TEST1.ID AND ID = TEST1.ID */ ON 1=1 /* WHERE TEST1.ID = TEST2.ID */ LEFT OUTER JOIN PUBLIC.TEST3 /* PUBLIC.PRIMARY_KEY_4C0: ID = TEST2.ID */ ON TEST2.ID = TEST3.ID WHERE (TEST3.ID IS NULL) AND (TEST1.ID = TEST2.ID)
> -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
> SELECT TEST1.ID, TEST2.ID, TEST3.ID FROM PUBLIC.TEST1 /* PUBLIC.TEST1.tableScan */ INNER JOIN PUBLIC.TEST2 /* PUBLIC.PRIMARY_KEY_4C: ID = TEST1.ID AND ID = TEST1.ID */ ON 1=1 /* WHERE TEST1.ID = TEST2.ID */ LEFT OUTER JOIN PUBLIC.TEST3 /* PUBLIC.PRIMARY_KEY_4C0: ID = TEST2.ID AND ID = NULL */ ON TEST2.ID = TEST3.ID WHERE (TEST3.ID IS NULL) AND (TEST1.ID = TEST2.ID)
> rows: 1
insert into test1 select x from system_range(2, 1000);
......@@ -3045,8 +3045,8 @@ inner join test2 on test1.id=test2.id
left outer join test3 on test2.id=test3.id
where test3.id is null;
> PLAN
> --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
> SELECT TEST1.ID, TEST2.ID, TEST3.ID FROM PUBLIC.TEST2 /* PUBLIC.TEST2.tableScan */ LEFT OUTER JOIN PUBLIC.TEST3 /* PUBLIC.PRIMARY_KEY_4C0: ID = TEST2.ID */ ON TEST2.ID = TEST3.ID INNER JOIN PUBLIC.TEST1 /* PUBLIC.PRIMARY_KEY_4: ID = TEST2.ID */ ON 1=1 WHERE (TEST3.ID IS NULL) AND (TEST1.ID = TEST2.ID)
> ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
> SELECT TEST1.ID, TEST2.ID, TEST3.ID FROM PUBLIC.TEST2 /* PUBLIC.TEST2.tableScan */ LEFT OUTER JOIN PUBLIC.TEST3 /* PUBLIC.PRIMARY_KEY_4C0: ID = TEST2.ID AND ID = NULL */ ON TEST2.ID = TEST3.ID INNER JOIN PUBLIC.TEST1 /* PUBLIC.PRIMARY_KEY_4: ID = TEST2.ID */ ON 1=1 WHERE (TEST3.ID IS NULL) AND (TEST1.ID = TEST2.ID)
> rows: 1
SELECT TEST1.ID, TEST2.ID, TEST3.ID
......@@ -3221,8 +3221,8 @@ call /* remark * / * /* ** // end */ 1;
> rows: 1
call (select x from dual where x is null);
> SELECT X FROM SYSTEM_RANGE(1, 1) /* PUBLIC.RANGE_INDEX */ /* scanCount: 2 */ WHERE X IS NULL
> --------------------------------------------------------------------------------------------
> SELECT X FROM SYSTEM_RANGE(1, 1) /* PUBLIC.RANGE_INDEX: X = NULL */ /* scanCount: 1 */ WHERE X IS NULL
> ------------------------------------------------------------------------------------------------------
> null
> rows: 1
......
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